Giúp mình giải bài nha:

V

vngocvien97

a/Ta có: $2009.2011=(2010-1)(2010+1)=2010^2-1$
Vậy $2010^2 > 2009.2010$
b/
$A=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)$
$=(2^2-1)(2^2+1)(2^4+1)(2^8+1)$
$=(2^4-1)(2^4+1)(2^8+1)$
$=2^{16}-1$
Vậy $A < B$
 
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