giúp mình giải 2 pt

H

heartrock_159

1.sin^3x.cosx - sinx.cos^3x=căn2/8
sinx.cosx(sin^2x-cos^2)=can2/8
-sin2x.cos2x= can2/4
sin4x=-can2/2=sin(-pi:4)
2.sinx + 2cosx=m(m là tham số)
ta co: pt co' nghiem <=> a^2+b^2 >=(lon hon hoac bang) c^2
<=> 5>=m^2
<=> |m| <= can 5
=>>>>>> Tu do bien luan, pt co nghiem khi nao
pt vo ngiem khi nao
Chuc Hoc Tot nhe'
 
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