giup minh cau tich phan nay voi

B

brit_nguyen

\int_{}^{}0_\prod_{i=1}^{n}/2(cosx+2)2^sinxdx
=\int_{}^{}0_\prod_{i=1}^{n}/2(cosx2^sinx)dx+\int_{}^{}0_\prod_{i=1}^{n}/2(2.2^sinx)dx
đặt sinx =t
cosxdx=dt
đổi cận
=\int_{}^{}2^tdt+\int_{}^{}2.2^tdt
=2^t/ln2+2.2^t/ln2
 
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