Giúp minh câu này

I

iceghost

$x^3-7x+6 \\
=x^3-x-6x+6 \\
=x(x^2-1)-6(x-1) \\
=x(x-1)(x+1)-6(x-1) \\
=(x-1)(x^2+x)-6(x-1) \\
=(x-1)(x^2+x-6) \\
=(x-1)(x^2-2x+3x-6) \\
=(x-1)[x(x-2)+3(x-2)] \\
=(x-1)(x+3)(x-2)$
 
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