T
taekwondo_01


Giải phương trình
1. [tex]\sqrt{x+\sqrt{x^2+1}}=\frac{9\sqrt{2}}{4}(x-1)\sqrt{x-1}[/tex]
2. [tex]13\sqrt{x-1}+9\sqrt{x+1}=16x[/tex]
1. [tex]\sqrt{x+\sqrt{x^2+1}}=\frac{9\sqrt{2}}{4}(x-1)\sqrt{x-1}[/tex]
2. [tex]13\sqrt{x-1}+9\sqrt{x+1}=16x[/tex]