Giúp mình bài tìm x:

N

nguyenbahiep1

[TEX]9 . (x - 3)^2 = (x^2 - 9)^2[/TEX]

[TEX] (x^2 - 9)^2 - (3. (x - 3))^2 = 0[/TEX]

[TEX] (x^2 -9 -3x +9)(x^2 -9 +3x -9) = 0[/TEX]

[TEX]x^2 -3x = 0[/TEX]

[TEX]x = 0[/TEX]

[TEX]x= 3[/TEX]

[TEX]x^2 +3x -18 = 0[/TEX]

[TEX]x = 3[/TEX]

[TEX] x= -6[/TEX]
 
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