giúp em với

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$(x.tanx)" = \dfrac{2}{(cosx)^2}-\dfrac{2x.sinx}{(cosx)^3}$

$x^2.(\dfrac{2}{(cosx)^2}-\dfrac{2xsinx}{(cosx)^3)}+2[x^2+x^2(tanx)^2](1+xtanx)$

$\dfrac{2x^2}{(cosx)^2}-\dfrac{2x^3.sinx}{(cosx)^3}-2[x^2(1+(tanx)^2][1+tanx]$

$\dfrac{2x^2}{(cosx)^2}-\dfrac{2x^3.sinx}{(cosx)^3}-2[\dfrac{x^2}{(cosx)^2}-\dfrac{2x^3.sinx}{(cosx)^3}$ = 0
 
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