[tex]=lim\frac{1-\sqrt{2x+1}}{\sqrt{3x+4}-x-2}-lim\frac{sinx}{\sqrt{3x+4}-x-2}=lim\frac{-2x.(\sqrt{3x+4}+x+2)}{(3x+4-(x+2)^2)(1+\sqrt{2x+1})}+lim\frac{sinx.(\sqrt{3x+4}+x+2)}{(3x+4-(x+2)^2}=lim\frac{2(\sqrt{3x+4}+x+2)}{(x+1)(1+\sqrt{2x+1})}+lim\frac{sinx.(\sqrt{3x+4}+x+2)}{-x(x+1)}[/tex]
bạn thế x=0 vào là đc. chú ý [tex]lim\frac{sinx}{x}=1[/tex]