O
o0o361996


tìm : lim (1-cos2x.cos4x)/2x
x->0
cho:
lim sinx/x =1
x->0
[/CENTER][/LEFT]
[/LEFT]
x->0
cho:
lim sinx/x =1
x->0
[/CENTER][/LEFT]
[/LEFT]
Last edited by a moderator: