Giao thoa ánh sáng....cứu em với !!!!!

K

kenylklee

N

nhoksad132

hjc!!!
ta co: Kx[lamda do?]xD/a=x => x=3D/a
goi buoc song can tjm la lamda!!!ta co:
Kx[lamda]xD/a=x thay x =3D/a ta co:
Kx[lamda]xD/a=3D/a
rut gon D/a=> lamda=3/k
Ma 0,4<lamda<0,75 hoac bang nua nha!!!=> k=5 6 7
vay co 3 vach sang cua á kahc nam trung o do!!!
Chuk ban thanh cong!!
 
Top Bottom