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Q

quynhsieunhan

$B=x^2+2y^2+2xy+2x-4y+2013$
b, $B = x^2 + 2y^2 + 2xy + 2x - 4y + 2013 = (x^2 + y^2 + 2xy + 2x + 2y + 1) + (y^2 - 6y + 9) + 2003$
= $(x + y + 1)^2 + (y - 3)^2 + 2003$ \geq $2003$
dấu bằng xảy ra khi $\left\{ \begin{array}{l} x = -4 \\ y =3 \end{array} \right.$
 
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