Giải toán 9

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heorungcodon0987

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chaugiang81

$\sqrt{25x} - \sqrt{16x}=9$
$<=>\sqrt{25} . \sqrt{x} - \sqrt{16} .\sqrt{x} =9$
$<=> 5\sqrt{x} -4\sqrt{x}=9$
$<=>(5-4)\sqrt{x}=9$
$<=>\sqrt{x}=9$
$<=>x=9^2$
$<=>x=81$
 
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