giải ptlg

N

nguyenbahiep1

8sinx =can3/cosx + 1/sinx

[laTEX]dk: cosx, sinx \not = 0 \\ \\ 8sin^2x.cosx = \sqrt{3}sinx +cosx \\ \\ 8tan^2x = \sqrt{3}tanx(1+tan^2x) + 1+tan^2x = 0 \\ \\ (\sqrt{3}tanx-1)(tan^2x-2\sqrt{3}tanx-1) = 0[/laTEX]
 
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