giải PTLG ze ot!!

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truongduong9083

$sin4x = \dfrac{1}{2}$
$\Leftrightarrow \left[ \begin{array}{l} 4x= \dfrac{\pi}{6}+k2\pi \\ 4x= \dfrac{5\pi}{6}+k2\pi \end{array} \right.$
$\Leftrightarrow \left[ \begin{array}{l} x= \dfrac{\pi}{24}+ k\dfrac{\pi}{2} \\ x= \dfrac{5\pi}{24}+ k\dfrac{\pi}{2}\end{array} \right.$
 
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