Đề nhầm chút rồi, đề đúng nên là: [imath]\dfrac{x+1}{2009} + \dfrac{x+3}{2007} = \dfrac{x+5}{2005} + \dfrac{x+17}{1993}[/imath]
[imath]\dfrac{x+1}{2009} + \dfrac{x+3}{2007} = \dfrac{x+5}{2005} + \dfrac{x+17}{1993} \\
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\Leftrightarrow \dfrac{x+1}{2009} + \dfrac{x+3}{2007} +2 = \dfrac{x+5}{2005} + \dfrac{x+17}{1993} +2 \\
\Leftrightarrow \left ( \dfrac{x+1}{2009} +1 \right ) + \left ( \dfrac{x+3}{2007} +1 \right ) = \left ( \dfrac{x+5}{2005} +1 \right ) + \left ( \dfrac{x+17}{1993} +1 \right ) \\
\Leftrightarrow \dfrac{x+2010}{2009} + \dfrac{x+2010}{2007} = \dfrac{x+2010}{2005}+ \dfrac{x+2010}{1993} \\
\Leftrightarrow (x+2010) \left ( \dfrac{1}{2009} + \dfrac{1}{2007} - \dfrac{1}{2005} - \dfrac{1}{1993} \right ) =0 \\
\Leftrightarrow x+2010=0 \Leftrightarrow x=-2010[/imath]