giải pt

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vipboycodon

2x+4−42x−6=x−72\sqrt{x+4}-4\sqrt{2x-6} = x-7
<=> 2(x+4−3)−4(2x−6−2)−(x−5)=02(\sqrt{x+4}-3)-4(\sqrt{2x-6}-2)-(x-5) = 0
<=> 2(x−5)x+4+3−4(2x−10)2x−6+2−(x−5)=0\dfrac{2(x-5)}{\sqrt{x+4}+3}-\dfrac{4(2x-10)}{\sqrt{2x-6}+2}-(x-5) = 0
<=> (x−5)(2x+4+3−82x−6+2−1)=0(x-5)(\dfrac{2}{\sqrt{x+4}+3}-\dfrac{8}{\sqrt{2x-6}+2}-1) = 0
<=> x=5x = 5
 
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