[tex]DK:-2\leq x\leq 2\\PT\Leftrightarrow \sqrt{2x+4}-2\sqrt{2-x}=\frac{12x-8}{\sqrt{9x^{2}+16}}\\\Leftrightarrow \frac{2x+4-4(2-x)}{\sqrt{2x+4}+2\sqrt{2-x}}=\frac{12x-8}{\sqrt{9x^{2}+16}}\\\Leftrightarrow \frac{6x-4}{\sqrt{2x+4}+2\sqrt{2-x}}=\frac{12x-8}{\sqrt{9x^{2}+16}}\\\Leftrightarrow (6x-4)(\frac{1}{\sqrt{2x+4}+2\sqrt{2-x}}-\frac{1}{\sqrt{9x^{2}+16}})=0\\TH1:6x-4=0\Leftrightarrow ...\\TH2:\sqrt{2x+4}+2\sqrt{2-x}=\sqrt{9x^{2}+16}\Leftrightarrow ...[/tex]
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