Nghĩ ra 1 cách đặt ẩn phụ ko hoàn toàn:
[tex]\sqrt{1-x^2}=t\Rightarrow 1=x^2+t^2[/tex]
[tex]x+2=3t+\sqrt{x^2+t^2+x}\Leftrightarrow x-3t+2=\sqrt{x^2+t^2+x}[/tex]
[tex]\Rightarrow x^2+9t^2+4-6tx+4x-12t=x^2+t^2+x[/tex]
[tex]\Rightarrow 4(2t^2-3t+1)+3x(1-2t)=0[/tex]
[tex]\Rightarrow 4(t-1)(2t-1)+3x(1-2t)=0[/tex]
[tex]\Rightarrow (1-2t)(3x-4t+4)=0[/tex]