(5x−1+x−1)(3x−1−5x2−6x+1)=4x→(5x−1+x−1)(3x−1−5x2−6x+1)−4x=0→5x−1−x−15x−1−x+1(3x−1−5x2−6x+1)−4x=0→5x−1−x−14x(3x−1−5x2−6x+1)−4x=0→4x(5x−1−x−13x−1−5x2−6x+1−1)=0→3x−1−5x2−6x+1−5x−1+x−1=0→3x−3−5x2−6x+1−5x−1+4+x−1=0→3x−3−(5x−1).(x−1)−5x−1+25x−1−4+x−1=0→3(x−1)−(5x−1).(x−1)−5x−1+25(x−1)+x−1=0→x−1(3x−1−5x−1−5x−1+25x−1+1)=0
Rôì suy ra 1 nghiệm x=1 giờ CM cái trong ngoặc 3x−1−5x−1−5x−1+25x−1+1=0→3x−1−3−5x−1+9+5x−1+25x−1−9−5x−1+5=0
Liên hợp nốt tìm dc nghiệm = 2 , tui mỏi tay rồi :V
(5x−1+x−1)(3x−1−5x2−6x+1)=4x→(5x−1+x−1)(3x−1−5x2−6x+1)−4x=0→5x−1−x−15x−1−x+1(3x−1−5x2−6x+1)−4x=0→5x−1−x−14x(3x−1−5x2−6x+1)−4x=0→4x(5x−1−x−13x−1−5x2−6x+1−1)=0→3x−1−5x2−6x+1−5x−1+x−1=0→3x−3−5x2−6x+1−5x−1+4+x−1=0→3x−3−(5x−1).(x−1)−5x−1+25x−1−4+x−1=0→3(x−1)−(5x−1).(x−1)−5x−1+25(x−1)+x−1=0→x−1(3x−1−5x−1−5x−1+25x−1+1)=0
Rôì suy ra 1 nghiệm x=1 giờ CM cái trong ngoặc 3x−1−5x−1−5x−1+25x−1+1=0→3x−1−3−5x−1+9+5x−1+25x−1−9−5x−1+5=0
Liên hợp nốt tìm dc nghiệm = 2 , tui mỏi tay rồi :V