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Giải phương trình sau:
[tex]4x^2-40x+99 [/tex] = [tex] 5\sqrt{3x-8}+5\sqrt{x+1} [/tex]
[tex]4x^2-40x+99 [/tex] = [tex] 5\sqrt{3x-8}+5\sqrt{x+1} [/tex]
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