Giải phương trình

L

lp_qt

đặt $y=\left (\sqrt{2+\sqrt{3}} \right )^{x} (y$ \geq $0)$

$\Longrightarrow \dfrac{1}{y}=\left (\sqrt{2-\sqrt{3}} \right )^{x}$

$\Longrightarrow y+\dfrac{1}{y}=4$

$\Longleftrightarrow \begin{bmatrix}y=2+\sqrt{3} & \\ y=2-\sqrt{3} & \end{bmatrix}$
 
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