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E

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DKXĐ: $1 \le x \le 2$

PT \Leftrightarrow $3(\sqrt{2-x}+1)=\sqrt{x+2}+\sqrt{x-1}$

\Leftrightarrow $3\sqrt{2-x}+2-\sqrt{x+2}+1-\sqrt{x-1}=0$

\Leftrightarrow $3\sqrt{2-x}+\dfrac{2-x}{\sqrt{x+2}+2}+\dfrac{2-x}{\sqrt{x-1}+1}=0$

\Leftrightarrow $x=2$
 
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