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shuieshushu


Giải các phương trình sau:
[TEX]a) \frac{1}{x} + \frac{1}{x+2} + \frac{1}{x+5} +\frac{1}{x+7} = \frac{1}{x+1} + \frac{1}{x+3} + \frac{1}{x+4} + \frac{1}{x+7}[/TEX]
[TEX]b){x}^{4} = 24x +32[/TEX]
[TEX]a) \frac{1}{x} + \frac{1}{x+2} + \frac{1}{x+5} +\frac{1}{x+7} = \frac{1}{x+1} + \frac{1}{x+3} + \frac{1}{x+4} + \frac{1}{x+7}[/TEX]
[TEX]b){x}^{4} = 24x +32[/TEX]
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