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huynhbachkhoa23

$\dfrac{1}{x^2+5x+4}+\dfrac{1}{x^2+11x+28}+\dfrac{1}{x^2+17x+70}=\dfrac{3}{4x-2}$

$\leftrightarrow \dfrac{3}{(x+1)(x+4)}+\dfrac{3}{(x+4)(x+7)}+\dfrac{3}{(x+7)(x+10)} = \dfrac{9}{4x-2}$

$\leftrightarrow \dfrac{1}{x+1}-\dfrac{1}{x+10}=\dfrac{9}{4x-2}$

$\leftrightarrow \dfrac{9}{(x+1)(x+10)}=\dfrac{9}{4x-2}$

$\leftrightarrow x^2+7x+12=0$

$\leftrightarrow$ $\left[\begin{matrix} x=-3 \\ x=-4\\ \end{matrix}\right.$
 
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