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nguyenbahiep1

[laTEX]\sqrt{x+1} + 2(x+1) = x-1 + \sqrt{1-x} + 3\sqrt{1-x^2} \\ \\ a + 2a^2 = -b^2+b+3ab \\ \\ a-b + 2a^2-3ab+b^2 = 0 \\ \\ (a-b) + (a-b)(2a-b) = 0 \\ \\ TH_1: a = b \Rightarrow x = 0 \\ \\ TH_2: 2\sqrt{x+1} - \sqrt{1-x} + 1 = 0 \\ \\ 2\sqrt{x+1} +1 = \sqrt{1-x} \\ \\ 4x+5 + 4\sqrt{x+1} = 1-x \\ \\ 4\sqrt{x+1} = -4-5x[/laTEX]
 
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