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[TEX]2Cos3x.Cosx +sqrt{3}(Sinx + Cosx)^2=2.sqrt{3}Cos^2 (2x-pi/4) [/TEX]
[TEX]PT \Leftrightarrow cos4x+cos2x+\sqrt{3}(1+sin2x)=\sqrt{3}(sin2x+cos2x)^2 \Leftrightarrow cos4x+cos2x+\sqrt{3}(1+sin2x)=\sqrt{3}(1+sin4x) \Leftrightarrow cos4x-\sqrt{3}sin4x+cos2x+\sqrt{3}sin2x=0 \Leftrightarrow sin(2x+\frac{\pi}{6})=sin(4x-\frac{\pi}{6})[/TEX]
 
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