giải phương trình vô tỉ

G

gakon2281997

S

soccan

$1,3$ tương tự
$\sqrt[3]{2x-1}=a\\
\sqrt[3]{x-1}=b\\
\longrightarrow \left\{\begin{matrix}a+b=1\\ a^3-2b^3=1\end{matrix}\right.\\
\longrightarrow x=1\\
2.\\
\sqrt{3x-2}+\sqrt{x-1}=t \longrightarrow 2\sqrt{(3x-2)(x-1)}=t^2-4x+3\\
pt \longleftrightarrow t^2-t-6=0\\
4.\\
\sqrt{x-1-2\sqrt{x-1}+1}+\sqrt{x-1-4\sqrt{x-1}+4}=1\\
\longleftrightarrow |\sqrt{x-1}-1|+|\sqrt{x-1}-2|=1$


 
Top Bottom