giai phuong trinh vo ti

B

braga

$$pt\iff 3\left[x^2-(x-1)\right]=\left(x+\sqrt{x-1}\right)^2$$
Đặt $\sqrt{x-1}=y\ge 0$
$$\implies 3(x^2-y^2)=(x+y)^2\iff (x+y)\left[3(x-y)-(x+y)\right]=0$$
 
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