Giải phương trình: [tex]\sqrt{3x+3}-\sqrt{6x-1}+18x^2-3x-2=0[/tex]
đk:[tex]x\geq \frac{1}{6}[/tex]
[tex]\Leftrightarrow \sqrt{3x+3}-2+\sqrt{6x-1}(\sqrt{6x-1}-1)+18x^2-9x+1=0[/tex]
[tex]\Leftrightarrow \frac{(3x-1)}{\sqrt{3x+3}+1}+\frac{\sqrt{6x-1}(3x-1)}{\sqrt{6x-1}+1}+(6x-1)(3x-1)=0[/tex]
[tex]\Leftrightarrow (3x-1)[\frac{1}{\sqrt{3x+3}+1}+\frac{\sqrt{6x-1}}{\sqrt{6x-1}+1}+(6x-1)]=0[/tex]
[tex]\Rightarrow x=\frac{1}{3}(t/m)[/tex]