T
thinhrost1


Giải phuơng trình nghiệm nguyên duơng:
a) $x^2+y^2=2011^{1995^k+1}(10-z)$
b) $x^2+y^2=399(10-z)$
c)$ x^2+y^2=11^{2k+1}(10-z)$
d) $x^2+y^2=15^{2k+1}(3-z)$
b) $x^2+y^2=399(10-z)$
c)$ x^2+y^2=11^{2k+1}(10-z)$
d) $x^2+y^2=15^{2k+1}(3-z)$