giải phương trình nghiệm nguyên

D

deat_stock

B

braga

$\fbox{1}. \ \dfrac{4}{a}+\sqrt[3]{4-b}=\sqrt[3]{4+4\sqrt{b}+b}+\sqrt[3]{4-4\sqrt{b}+b}$
$\iff \dfrac{4}{a}+\sqrt[3]{(2-\sqrt{b})(2+\sqrt{2}}=\sqrt[3]{(2+\sqrt{b})^2}+\sqrt[3]{(2-\sqrt{b})^2}$
Đất
$\sqrt[3]{2+\sqrt{b}}=x$
$\sqrt[3]{2-\sqrt{b}}=y$
Ta có hệ sau:
$\left\{\begin{matrix} x^3+y^3=4\\ \frac{4}{a}+xy=x^2+y^2 \end{matrix}\right.$
 
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