giải pt: [TEX]cos(4/3)x=cos^2x[/TEX]
[tex]pt\Leftrightarrow 1+cos2x=2cos\left ( \frac{4x}{3} \right )[/tex]
Đặt [tex]\frac{4x}{3}=2a\Rightarrow 2x=3a[/tex]
[tex]pt\Leftrightarrow cos3a+1=2cos2a\Leftrightarrow 4cos^3a-3cosa+1=2(2cos^2a-1)[/tex]
Giải pt bậc 3 => a => x