Giải phương trình lg

L

lovelycat_handoi95

[TEX] \Leftrightarrow 2sin3xsinx+2\sqrt{3}cosxsin3x=2\\ \Leftrightarrow -(cos4x-cos2x)+\sqrt{3}(sin4x+sin2x)=4 \\ \Leftrightarrow sin(4x-\frac{\pi}{6})+sin(2x+\frac{\pi}{6})=2 [/TEX]

[TEX] NX : \left{sin(4x-\frac{\pi}{6}) \leq 1 \\ sin(2x+\frac{\pi}{6}) \leq 1 [/TEX]

[TEX] \Leftrightarrow \left{sin(4x-\frac{\pi}{6}) = 1 \\ sin(2x+\frac{\pi}{6}) = 1[/TEX]

[TEX]\Leftrightarrow x= \frac{\pi}{6}+k\pi ( k \in Z)[/TEX]
 
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