Giải hệ phương trình:
View attachment 154761
[tex](1) <=> x^2+(y+1)^2=x.(y+1)+1\\\\ => a^2+b^2=ab+1 (x=a; y+1=b)\\\\ => a^2-ab+b^2=1\\\\ +, (2) <=> 2a^3=(a+b).1=(a+b).(a^2-ab+b^2)\\\\ <=> 2a^3=a^3+b^3 <=> a=b => x=y+1\\\\ => (1) <=> x^2+x^2=x.x+1 <=> x^2=1 <=>...[/tex]