giải gúp minh nha.. cần gấp!hjhjhj

N

newstarinsky

$I=\int_{0}^{\dfrac{\pi}{4}}\dfrac{1-cos2x}{2}dx\\
=\dfrac{1}{2}x-\dfrac{1}{4}sin2x\\
=\dfrac{\pi}{8}-\dfrac{1}{4}\\
=\dfrac{\pi-2}{8}$
 
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