giải giùm mình bài toán này được ko

H

hiensau99

[TEX]A=\frac{2010^{2010}+1}{2010^{2011}+1}[/TEX]
\Rightarrow [TEX]2010A=\frac{2010^{2011}+2010}{2010^{2011}+1}=1+ \frac{2009}{2010^{2011}+1}[/TEX]

[TEX]B=\frac{2010^{2011}+1}{2010^{2012+1}[/TEX]
\Rightarrow[TEX]2010B=\frac{2010^{2012}+2010}{2010^{2012}+1}=1+ \frac{2009}{2010^{2012}+1}[/TEX]

Ta có: [TEX]\frac{2009}{2010^{2011}+1}>\frac{2009}{2010^{2012}+1} \Rightarrow 2010A>2010B \Rightarrow A>B[/TEX]
 
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