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hung_ils

[TEX]2^{4log^{2}_{2}x}+x^{2log_{2}x}-20\leq 0\\\\log_{2}x=t\Rightarrow x=2^{t}\Rightarrow 2^{4t^2}+(2^t)^{2t}-20\leq 0\\\\\Leftrightarrow 2^{4t^2}+2^{2t^2}-20\leq 0\Leftrightarrow (2^{2t^2}+5)*(2^{2t^2}-4)\leq 0\\\\ \Rightarrow 2^{2t^2}\leq 4(2^{2t^2}+5>0 \forall t)\Rightarrow 2^{2t^2}\leq 2^2\\\\\Rightarrow t^2\leq 1\Rightarrow -1\leq t\leq 1\Rightarrow -1\leq log_{2}x\leq 1\Rightarrow \frac{1}{2}\leq x\leq 1[/TEX]
PS:Hơi khó nhìn nhỉ.......................
 
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