giá trị lớn nhất 8

K

khaiproqn81

$5-8x-x^2=-(x^2+8x-5)=-(x^2+8x+16-21)=21-(x+4)^2 \le 21. \mathfrak{Dấu} "=" \mathfrak{xảy} \mathfrak{ra} \mathfrak{khi} x=-4$
 
K

khaiproqn81

$-4x^2-4x-2 = -(4x^2+4x+2)=-(4x^2+4x+1+1)=-1-(2x+1)^2 \le -1$

Dấu $"="$ xảy ra khi $x=\dfrac{-1}{2}$
 
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