đồng dư thức

T

tiopow

Câu a nè:
Theo đồng dư thức ta có:
[TEX] 2^10 [/TEX][TEX]\equiv 1 [/TEX] (mod 11)
[TEX] 3^4n+1 \equiv 3^4n [/TEX].3 (mod 10)
\Rightarrow[TEX]3^4n+1 [/TEX] = 10k + 3
\Rightarrow[TEX]2^3^(4n+1)[/TEX] = [TEX] 2^10k+3 \equiv 2^3 (mod 11)\equiv 8[/TEX] (mod 11)
\Rightarrowdpcm
 
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