Đồng Nai hôm qua
nguồn : sưu tầm
Câu 5.4
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Giải:
Ta có: AB=MN suy ra: AM=BN
Ta có: [tex]\frac{AC}{CQ}=\frac{AB}{BN}(BC\parallel QN,Talet)[/tex]
[tex]\Leftrightarrow \frac{AC}{CQ}=\frac{AB}{AM}(AM=BN)\Rightarrow \frac{AC}{CQ}=\frac{EB}{EP}\Rightarrow \frac{AC}{EB}=\frac{CQ}{EP}[/tex]
Mà: [tex]\Delta ACH\sim \Delta BEH(g.g)\Rightarrow \frac{AC}{BE}=\frac{CH}{EH}[/tex]
Suy ra: [tex]\frac{CH}{EH}=\frac{CQ}{EP}[/tex]
Xét [tex]\Delta QCH ;\Delta PEH[/tex] có:
[tex]\widehat{QCH}=\widehat{EPH}(=90^{\circ});\frac{QC}{EP}=\frac{CH}{HE}[/tex]
[tex]\Rightarrow \Delta QCH\sim \Delta PEH(c.g.c)\Rightarrow \widehat{CQH}=\widehat{EPH}\Rightarrow DQHP[/tex] nội tiếp (ĐPCM)