Đề thi Toán 8

D

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(a+b+c)^3 = (a+b)^3+c^3+3c(a+b)(a+b+c)
= a^3+b^3+c^3+ 3ab(a+b)+3c(a+b)(a+b+c)
= a^3+b^3+c^3+ 3(a+b)(ab+ac+bc+c^2)
= a^3+b^3+c^3+ 3(a+b)(a+c)(b+c)
=>(a+b+c)^3 - a^3-b^3-c^3=3(a+b)(b+c)(c+a)
 
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