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papy__kut3


[TEX]2(sin^4 + cos^4) + cos4x + 2sin2x = 0[/TEX]
[TEX](\frac{sin^4x + cos^4}{5sin2x})=(\frac{1}{2}cotg2x-\frac{1}{8sin2x})[/TEX]
[TEX](\frac{sin^4x + cos^4}{5sin2x})=(\frac{1}{2}cotg2x-\frac{1}{8sin2x})[/TEX]