Cho S= 1/2 + 1/3 + 1/4 + ... + 1/48+1/49/1/50 và P = 1/49 + 2/48 + 3/47 + ... +48/2 + 49/1
Tính S/P
-Ta có:
$P=\frac{1}{49}+\frac{2}{48}+\frac{3}{47}+...+\frac{48}{2}$
$P=(\frac{1}{49}+1)+(\frac{2}{48}+1)+...+(\frac{48}{2}+1+1)$
$P=\frac{50}{49}+\frac{50}{48}+...+\frac{50}{2}+\frac{50}{50}$
$P=50(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{49}+\frac{1}{50})$
$\Rightarrow \frac{S}{P}=\frac{(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{50})}{50(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{50})}=\frac{1}{50}$
-Vậy...