dasfadsfgagad

L

lovelybaby92

ta có : a = \frac{-x^3 + 4}{x^2} = f(x)

f'(x) = -1 - \frac{8}{x^3}

f'(x) = 0 \Leftrightarrow \frac{8}{x^3} = -1

\Leftrightarrow x = -2
 
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