Cho abc=1. Cmr: [tex]P=\frac{1}{1+a+ab}+\frac{1}{1+b+bc}+\frac{1}{1+c+ca}=1[/tex]
thay 1= abc vao P ta có:
[tex]\frac{abc}{abc+a+ab}+\frac{1}{bc+b+1}+\frac{b}{bc+abc+b} =\frac{bc}{bc+b+1}+\frac{1}{bc+c+1} +\frac{b}{bc+b+1} =\frac{bc+b+1}{bc+b+1}=1[/tex]
tham khảo nha bạn