Ta có: [TEX]5^2\equiv 1\pmod{12}\Rightarrow \left (5^2 \right )^{35}\equiv 1\pmod{12} \ \text{hay} \ 5^{70}\equiv 1\pmod{12} \ \ (1)[/TEX]
[TEX]7^2\equiv 1\pmod{12}\Rightarrow \left (7^2 \right )^{25}\equiv 1\pmod{12} \ \text{hay} \ 7^{50}\equiv 1\pmod{12} \ \(2)[/TEX]
Từ (1) và (2) [TEX]\Rightarrow 5^{70}+7^{50}[/TEX] chia 12 dư 2
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