dai so lop 8

M

minhhieupy2000

Ta có
$ (2x+a)^{2}=(bx+5)^{2}$
$\left[\begin{matrix} (2x+a)=bx+5 (1)\\2x+a=-bx-5 (2)\end{matrix}\right.$
$(1) \ \ x(2-b) = 5-a$

\Rightarrow $x= \dfrac{5-a}{2-b}$

$(2)$ \Rightarrow $x=-\dfrac{5+a}{2+b}$
Có vẻ như thiếu đk quan hệ giữa a,b,c :D
 
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