[tex]\frac{2x^2-x+2}{2x-1}=x+\frac{2}{2x-1}=\frac{1}{2}.(2x-1)+\frac{2}{2x-1}+\frac{1}{2}\geq 2\sqrt{\frac{1}{2}(2x-1).\frac{2}{2x-1}}+\frac{1}{2}=2+\frac{1}{2}=\frac{5}{2}[/tex]
dấu bằng xảy ra khi [tex]\frac{1}{2}(2x-1)=\frac{2}{2x-1}<=>(2x-1)^2=4=>x=\frac{3}{2}[/tex]