Đại số 8

V

vipboycodon

$(3x+1)^2-(3x-2)(3x+2)=14$
<=> $9x^2+6x+1-(9x^2-4)=14$
<=> $9x^2+6x+1-9x^2+4=14$
<=> $6x+5=14$
<=> $6x = 9$
<=> $x = \dfrac{3}{2}$
 
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