Đại số 8

T

thong7enghiaha

1.

$\dfrac{x^5+x+1}{x^3+x^2+x}$

$=\dfrac{x^5+x^4+x^3+x^2+x+1-x^4-x^3-x^2}{x(x^2+x+1)}$

$=\dfrac{x^3(x^2+x+1)+(x^2+x+1)-x^2(x^2+x+1)}{x(x^2+x+1)}$

$=\dfrac{(x^2+x+1)(x^3-x^2+1)}{x(x^2+x+1)}$

$=\dfrac{x^3-x^2+1}{x}$
 
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